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From:Craig \(OFT\) Weston Date:September 28 2007 6:01pm
Subject:RE: Count syntax
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Beauford, you might find this article on cross joins interesting, it was
something shown to me a few weeks ago that discusses this kind of
function.

http://dev.mysql.com/tech-resources/articles/wizard/print_version.html
Cheers,
craig


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-----Original Message-----

From: Michael Dykman [mailto:mdykman@stripped] 
Sent: Friday, September 28, 2007 1:36 PM
To: Beauford
Cc: mysql@stripped
Subject: Re: Count syntax

1 means that 1 will be added to the sum if the condition tests,
otherwise 0 will be added to the sum.  the condition in this case is
(supportertype = 'L') and will be applied to every row.

On 9/28/07, Beauford <php-list-user@stripped> wrote:
> Thanks - it works, but what does the 1 and 0 do in this -
> SUM(IF(supportertype = 'L', 1, 0))
>
> > -----Original Message-----
> > From: Baron Schwartz [mailto:baron@stripped]
> > Sent: September 28, 2007 1:00 PM
> > To: Beauford
> > Cc: mysql@stripped
> > Subject: Re: Count syntax
> >
> > Beauford wrote:
> > > Hi,
> > >
> > > I have the following line of code and I keep getting wrong
> > results from it.
> > > Can someone let me know what I'm doing wrong here. I just
> > can't quite
> > > figure out the syntax that I need.
> > >
> > > select count(*) as numrows, count(supportertype) as leadcar from
> > > registrar where supportertype = 'L';
> > >
> > > What I want to do is count the total number of records and then
the
> > > total number of records that have "L" as the supportertype
> > and then display them.
> > >
> > > So I should have something like "There are 100 total records and
22
> > > with Supporter Type L".
> >
> > Try this:
> >
> > SELECT COUNT(*), SUM(IF(supportertype = 'L', 1, 0)) FROM registrar;
> >
> > Baron
> >
> > --
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> >
> >
> >
>
>
>
>
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>


-- 
 - michael dykman
 - mdykman@stripped

 - All models are wrong.  Some models are useful.

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Thread
Count syntaxBeauford28 Sep
  • Re: Count syntaxBaron Schwartz28 Sep
    • RE: Count syntaxBeauford28 Sep
      • Re: Count syntaxMichael Dykman28 Sep
        • RE: Count syntaxCraig \(OFT\) Weston28 Sep
        • RE: Count syntaxBeauford29 Sep