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From:Mark Unwin Date:September 22 2005 6:07am
Subject:Comparison of table entries in the same table
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I have a 'software' table in my database, as described below.
The field software_uuid is a link to a specific machine, in another
table.
I run a scan each day, and populate this table - not deleting anything.
This data is input ONLY - no queries can be run, only an insert.
The client cannot actually talk to the database, it passes the
information to a second PC that can. The second PC can't talk back to
the client, it only accepts the SQL inserts, and sends them to the
database.
Each scan would generate new software_id, and a different timestamp -
most other stuff would be the same (assuming nothing installed or
removed). The fields software_detect_date, software_detect_current_scan
& software_no_detect_date are not currently used - they are left over
from a previous incarnation. They can be removed or used, as needed.
How can I compare the results of all scans run against a given machine,
and return what has been installed & removed between each scan (if
anything). Basically an audit trail.

IE - For machine name test_pc

Software_uuid  |  software_name     |  software_timestamp  |  
----------------------------------------------------------------------
test_pc        |  WinRAR            |  20050905090000      |  detected
test_pc        |  Adobe Acrobat     |  20050905090000      |  not
detected
test_pc        |  WinZip 8.0        |  20050901090000      |  detected
test_pc        |  MS Office 2003    |  20050901090000      |  detected
test_pc        |  Adobe Acrobat     |  20050901090000      |  detected

Or something similar.
Extending on this, how can I return all software detected in the last x
days ?
I have been using the following to return a list of machines and their
latest timestamp from another table called 'system'.
select system_uuid, MAX(system_timestamp) from system group by
system_uuid
This is working fine.
Another looping query I have to return all software from a given
machine, on it's latest scan is
<<system_uuid is provided>>
select system_uuid, MAX(system_timestamp) AS timestamp from system group
by system_uuid
<<from this we get the latest timestamp>>
INSERT into software_temp SELECT software_name, software_timestamp,
software_uuid FROM software WHERE software_uuid = '$system_uuid' AND
software_timestamp = '$timestamp'
<<We get a list of currently installed software>>

This is all done in PHP.
Hope that's not too much info (better to provide too much, rather than
not enough).
 
Any help much appreciated.
 
Mark Unwin.
 
+------------------------------+---------------------+------+-----+-----
----+----------------+
| Field                        | Type                | Null | Key |
Default | Extra          |
+------------------------------+---------------------+------+-----+-----
----+----------------+
| software_id                  | int(10) unsigned    |      | PRI | NULL
| auto_increment |
| software_uuid                | varchar(100)        |      |     |
|                |
| software_name                | text                | YES  |     | NULL
|                |
| software_version             | text                | YES  |     | NULL
|                |
| software_location            | text                | YES  |     | NULL
|                |
| software_uninstall           | text                | YES  |     | NULL
|                |
| software_install_date        | text                | YES  |     | NULL
|                |
| software_publisher           | text                | YES  |     | NULL
|                |
| software_install_source      | text                | YES  |     | NULL
|                |
| software_detect_date         | date                | YES  |     | NULL
|                |
| software_detect_current_scan | varchar(20)         | YES  |     | NULL
|                |
| software_no_detect_date      | date                | YES  |     | NULL
|                |
| software_system_component    | char(2)             | YES  |     | NULL
|                |
| software_timestamp           | bigint(20) unsigned | YES  |     | NULL
|                |
+------------------------------+---------------------+------+-----+-----
----+----------------+



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Thread
Comparison of table entries in the same tableMark Unwin22 Sep