Okay, I'm beatin' myself up, and 4900 archived mysql messages later,
still dying on the vine.
Doing a feedback form in PHP. Works fine. Inserts the record. Code
follows:
$link = mysql_connect($dbhost, $dbuser, $dbpasswd);
mysql_select_db($db,$link);
$Result=mysql_query("INSERT INTO $dbtable VALUES ('', '$UserAgent',
'$Referer',
'$ScriptFilename', '$HitTime', '$RemoteHost', '$RemoteAddr',
'$EmployeeRating', '$SafeComments','$FullName','$eMail')", $link);
$CommentId=$Result[1];
echo "<center>CommentId=$CommentId; Result=$Result";
mysql_close($Result);
Yields:
Warning: Variable $Result is not an array or string in
insertfeedback.php3 on line 16
--and--
CommentId=; Result=1
Paul, Monty, Fred... someone not out enjoying their Saturday nite wanna
kick me in the a$$ with where I'm goofin'?
Regards,
Van
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