From: Benaya Paul
Date: November 22 2012 2:53pm
Subject: Re: Basic SELECT help
List-Archive: http://lists.mysql.com/mysql/228685
Message-Id: <CABsOb=YO9KK3n18Zr9J+QHPBbxTbVBgKdK3smQ0SAPiuTfW=aQ@mail.gmail.com>
MIME-Version: 1.0
Content-Type: multipart/alternative; boundary=e89a8f838d8dc8e59a04cf16a02f

--e89a8f838d8dc8e59a04cf16a02f
Content-Type: text/plain; charset=ISO-8859-1

U can remove the type field it will work
On Nov 22, 2012 8:21 PM, "Neil Tompkins" <neil.tompkins@stripped>
wrote:

> Basically I only what to return the IDs that have both types.
>
>
> On Thu, Nov 22, 2012 at 2:39 PM, marek gutowski <marek.gutowski@stripped
> >wrote:
>
> > SELECT DISTINCT id FROM table WHERE type IN ('2','5')
> >
> > should work
> >
> >
> > On 22 November 2012 14:30, Neil Tompkins <neil.tompkins@stripped
> >wrote:
> >
> >> Hi,
> >>
> >> I'm struggling with what I think is a basic select but can't think how
> to
> >> do it : My data is
> >>
> >> id,type
> >>
> >> 1000,5
> >> 1001,5
> >> 1002,2
> >> 1001,2
> >> 1003,2
> >> 1005,2
> >> 1006,1
> >>
> >> From this I what to get a distinct list of id where the type equals 2
> and
> >> 5
> >>
> >> Any ideas ?
> >>
> >> Neil
> >>
> >
> >
>

--e89a8f838d8dc8e59a04cf16a02f--