On Mar 17, 2011, at 3:01 PM, Geert-Jan Brits wrote:
> Indeed, I don't thing there is.
>
> Just be sure that each record has an unique combination of org_id
> and item_id, otherwise you might end up with an org_id that, for
> example, references 4 times item_id 34 in 4 different records, but
> no other item_ids. This is obvisouly not what you want.
>
> Geert-Jan
Correct. That's why I use "select distinct org_id, item_id" in sub-
query.
Is here anybody from mysql development team, to suggest to build IN
ALL function?
:-)
>
> 2011/3/17 LAMP <lamp@stripped>
> First I was thinking there is function IN ALL or something like
> that, since there are functions IN and EXISTS. And I would be able
> to make a query something like this
> select distinct org_id, item_id
> from orders
> where item_id in all (34, 36, 58, 63)
> order by org_id asc
>
> But, there isn't any. :-(
>
>
> The correct query is
>
> select r.org_id
> from
> (
> select distinct a.org_id, a.item_id
> from orders a
> where a.item_id in (34, 36, 58, 63)
> order by a.org_id asc
> ) r
> group by r.org_id
> having count(*) >= 4
>
>
>
>
>
>
>
>
> On Mar 17, 2011, at 12:24 PM, Peter Brawley wrote:
>
> > What I need is a list of orgs they bought all of items 34, 36, 58,
> 63. every of them.
>
> Some solutions under "What else did buyers of X buy" at
> http://www.artfulsoftware.com/infotree/queries.php
> .
>
> PB
>
> ---
>
> On 3/17/2011 12:00 PM, LAMP wrote:
> Yes, that was my question. Though, since English is not my first
> language, let me try to post it again:
>
> There is a list of all orgs and items org bough, from table called
> orders
>
> item_id org_id
> 34 2607
> 34 2607
> 34 1520
> 36 2607
> 36 1520
> 36 8934
> 38 28
> 38 15
> 38 5
> 38 13
> 58 2607
> 58 2607
> 58 7295
> 58 1649
> 58 7295
> 58 1520
> 63 2607
> 63 2607
> 63 8871
> 63 7295
> 63 1520
> 65 15
> 65 20
> 95 1520
> 95 1520
> 95 7295
> 98 1520
> 98 7295
>
>
> select org_id from orders where item_id in (34. 36. 58. 63) will
> give me a result
>
> 5
> 13
> 15
> 28
> 1520
> 1649
> 2607
> 7295
> 8871
> 8934
>
> This is the list of ALL orgs they bought ANY of items (34. 36. 58.
> 63). Agree?
>
> What I need is a list of orgs they bought all of items 34, 36, 58,
> 63. every of them. Result should be only orgs 2607 and 1520.
>
> I hope it's more clear now.
>
>
>
> On Mar 15, 2011, at 10:47 PM, Rhino wrote:
>
>
> Your original question said: "Need to select all (distinct) org_id
> they have item_id 34, 36, 58 and 63. All of them, not only some of
> them. "
>
> That's the question I answered with my suggested query.
>
> It sounds like that is not what you meant after all but I'm not sure
> what you DO want with your query. Why are 2607 and 1520 the only
> right answers?
>
> Because they are. I look at the database and "manually" found the
> result I have to get. What's wrong with my statement?
>
> Based on your own query, it looks like you only want an org_id for
> item_ids 34, 36, 58, and 63 if there are exactly 4 occurrences of
> that org_id amongst the desired item_ids
>
> actually, there is mistake in my query, it should say "having
> count(org_id) >= 4"
> and, yes, that's what I want. I can get the correct list using the
> query I posted but I was hoping there is BETTER way.
>
> but that wasn't in your statement of the problem. So please clarify
> EXACTLY what you want. Giving an incomplete or contradictory
> description of you want only wastes both your time and mine.
>
> As I stated earlier, English is not my first language and I was
> trying to do my best. Sorry for confusing you.
>
>
>
> --
> Rhino
>
> On 2011-03-15 20:35, LAMP wrote:
>
> On Mar 15, 2011, at 6:18 PM, Rhino wrote:
>
>
> All you should need is this:
>
> select distinct org_id
> from orders
> where item_id in (34, 36, 58, 63)
>
> I'm assuming that the DISTINCT operator is available in the version
> of MySQL that you are using. I don't currently have any version of
> MySQL installed so I can't try this myself to be sure it works in
> your version of MySQL.
>
> --
> Rhino
>
> your query will give me every org_id that has ANY of item_id., I
> need org_id that has ALL of item_id. right?
> result would be
> 2607
> 1520
> 8934
> 7295
> 1649
> 8871
>
>
>
>
> On 2011-03-15 18:51, LAMP wrote:
> Hi,
> I need a help to build a query.
>
> Let's say there is a table orders (simplified, of course)
>
> CREATE TABLE orders (
> `item_id` int,
> `org_id` int,
> ) ENGINE=MyISAM
>
>
> item_id org_id
> 34 2607
> 34 2607
> 34 1520
> 36 2607
> 36 1520
> 36 8934
> 38 28
> 38 15
> 38 5
> 38 13
> 58 2607
> 58 2607
> 58 7295
> 58 1649
> 58 7295
> 58 1520
> 63 2607
> 63 2607
> 63 8871
> 63 7295
> 63 1520
> 65 15
> 65 20
> 95 1520
> 95 1520
> 95 7295
> 98 1520
> 98 7295
>
>
> Need to select all (distinct) org_id they have item_id 34, 36, 58
> and 63. All of them, not only some of them.
>
> Result is org_id=2607 and org_id=1520
>
> I can have it by
>
> select org_id
> from orders
> where item_id in (34, 36, 58, 63)
> group by org_id
> having count(org_id)=4
>
> but, I'm sure there is better solution?
>
> Thanks for any help.
>
> LAMP
>
>
>
>
>
>
>
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