First I was thinking there is function IN ALL or something like that,
since there are functions IN and EXISTS. And I would be able to make a
query something like this
select distinct org_id, item_id
from orders
where item_id in all (34, 36, 58, 63)
order by org_id asc
But, there isn't any. :-(
The correct query is
select r.org_id
from
(
select distinct a.org_id, a.item_id
from orders a
where a.item_id in (34, 36, 58, 63)
order by a.org_id asc
) r
group by r.org_id
having count(*) >= 4
On Mar 17, 2011, at 12:24 PM, Peter Brawley wrote:
> > What I need is a list of orgs they bought all of items 34, 36, 58,
> 63. every of them.
>
> Some solutions under "What else did buyers of X buy" at
> http://www.artfulsoftware.com/infotree/queries.php
> .
>
> PB
>
> ---
>
> On 3/17/2011 12:00 PM, LAMP wrote:
>> Yes, that was my question. Though, since English is not my first
>> language, let me try to post it again:
>>
>> There is a list of all orgs and items org bough, from table called
>> orders
>>
>> item_id org_id
>> 34 2607
>> 34 2607
>> 34 1520
>> 36 2607
>> 36 1520
>> 36 8934
>> 38 28
>> 38 15
>> 38 5
>> 38 13
>> 58 2607
>> 58 2607
>> 58 7295
>> 58 1649
>> 58 7295
>> 58 1520
>> 63 2607
>> 63 2607
>> 63 8871
>> 63 7295
>> 63 1520
>> 65 15
>> 65 20
>> 95 1520
>> 95 1520
>> 95 7295
>> 98 1520
>> 98 7295
>>
>>
>> select org_id from orders where item_id in (34. 36. 58. 63) will
>> give me a result
>>
>> 5
>> 13
>> 15
>> 28
>> 1520
>> 1649
>> 2607
>> 7295
>> 8871
>> 8934
>>
>> This is the list of ALL orgs they bought ANY of items (34. 36. 58.
>> 63). Agree?
>>
>> What I need is a list of orgs they bought all of items 34, 36, 58,
>> 63. every of them. Result should be only orgs 2607 and 1520.
>>
>> I hope it's more clear now.
>>
>>
>>
>> On Mar 15, 2011, at 10:47 PM, Rhino wrote:
>>
>>>
>>> Your original question said: "Need to select all (distinct) org_id
>>> they have item_id 34, 36, 58 and 63. All of them, not only some of
>>> them. "
>>>
>>> That's the question I answered with my suggested query.
>>>
>>> It sounds like that is not what you meant after all but I'm not
>>> sure what you DO want with your query. Why are 2607 and 1520 the
>>> only right answers?
>>
>> Because they are. I look at the database and "manually" found the
>> result I have to get. What's wrong with my statement?
>>
>>> Based on your own query, it looks like you only want an org_id for
>>> item_ids 34, 36, 58, and 63 if there are exactly 4 occurrences of
>>> that org_id amongst the desired item_ids
>>
>> actually, there is mistake in my query, it should say "having
>> count(org_id) >= 4"
>> and, yes, that's what I want. I can get the correct list using the
>> query I posted but I was hoping there is BETTER way.
>>
>>> but that wasn't in your statement of the problem. So please
>>> clarify EXACTLY what you want. Giving an incomplete or
>>> contradictory description of you want only wastes both your time
>>> and mine.
>>
>> As I stated earlier, English is not my first language and I was
>> trying to do my best. Sorry for confusing you.
>>
>>
>>>
>>> --
>>> Rhino
>>>
>>> On 2011-03-15 20:35, LAMP wrote:
>>>>
>>>> On Mar 15, 2011, at 6:18 PM, Rhino wrote:
>>>>
>>>>>
>>>>> All you should need is this:
>>>>>
>>>>> select distinct org_id
>>>>> from orders
>>>>> where item_id in (34, 36, 58, 63)
>>>>>
>>>>> I'm assuming that the DISTINCT operator is available in the
>>>>> version of MySQL that you are using. I don't currently have any
>>>>> version of MySQL installed so I can't try this myself to be sure
>>>>> it works in your version of MySQL.
>>>>>
>>>>> --
>>>>> Rhino
>>>>
>>>> your query will give me every org_id that has ANY of item_id., I
>>>> need org_id that has ALL of item_id. right?
>>>> result would be
>>>> 2607
>>>> 1520
>>>> 8934
>>>> 7295
>>>> 1649
>>>> 8871
>>>>
>>>>
>>>>
>>>>>
>>>>> On 2011-03-15 18:51, LAMP wrote:
>>>>>> Hi,
>>>>>> I need a help to build a query.
>>>>>>
>>>>>> Let's say there is a table orders (simplified, of course)
>>>>>>
>>>>>> CREATE TABLE orders (
>>>>>> `item_id` int,
>>>>>> `org_id` int,
>>>>>> ) ENGINE=MyISAM
>>>>>>
>>>>>>
>>>>>> item_id org_id
>>>>>> 34 2607
>>>>>> 34 2607
>>>>>> 34 1520
>>>>>> 36 2607
>>>>>> 36 1520
>>>>>> 36 8934
>>>>>> 38 28
>>>>>> 38 15
>>>>>> 38 5
>>>>>> 38 13
>>>>>> 58 2607
>>>>>> 58 2607
>>>>>> 58 7295
>>>>>> 58 1649
>>>>>> 58 7295
>>>>>> 58 1520
>>>>>> 63 2607
>>>>>> 63 2607
>>>>>> 63 8871
>>>>>> 63 7295
>>>>>> 63 1520
>>>>>> 65 15
>>>>>> 65 20
>>>>>> 95 1520
>>>>>> 95 1520
>>>>>> 95 7295
>>>>>> 98 1520
>>>>>> 98 7295
>>>>>>
>>>>>>
>>>>>> Need to select all (distinct) org_id they have item_id 34, 36,
>>>>>> 58 and 63. All of them, not only some of them.
>>>>>>
>>>>>> Result is org_id=2607 and org_id=1520
>>>>>>
>>>>>> I can have it by
>>>>>>
>>>>>> select org_id
>>>>>> from orders
>>>>>> where item_id in (34, 36, 58, 63)
>>>>>> group by org_id
>>>>>> having count(org_id)=4
>>>>>>
>>>>>> but, I'm sure there is better solution?
>>>>>>
>>>>>> Thanks for any help.
>>>>>>
>>>>>> LAMP
>>>>>>
>>>>
>>>>
>>
>>
