> What I need is a list of orgs they bought all of items 34, 36, 58,
63. every of them.
Some solutions under "What else did buyers of X buy" at
http://www.artfulsoftware.com/infotree/queries.php.
PB
---
On 3/17/2011 12:00 PM, LAMP wrote:
> Yes, that was my question. Though, since English is not my first
> language, let me try to post it again:
>
> There is a list of all orgs and items org bough, from table called orders
>
> item_id org_id
> 34 2607
> 34 2607
> 34 1520
> 36 2607
> 36 1520
> 36 8934
> 38 28
> 38 15
> 38 5
> 38 13
> 58 2607
> 58 2607
> 58 7295
> 58 1649
> 58 7295
> 58 1520
> 63 2607
> 63 2607
> 63 8871
> 63 7295
> 63 1520
> 65 15
> 65 20
> 95 1520
> 95 1520
> 95 7295
> 98 1520
> 98 7295
>
>
> select org_id from orders where item_id in (34. 36. 58. 63) will give
> me a result
>
> 5
> 13
> 15
> 28
> 1520
> 1649
> 2607
> 7295
> 8871
> 8934
>
> This is the list of ALL orgs they bought ANY of items (34. 36. 58.
> 63). Agree?
>
> What I need is a list of orgs they bought all of items 34, 36, 58, 63.
> every of them. Result should be only orgs 2607 and 1520.
>
> I hope it's more clear now.
>
>
>
> On Mar 15, 2011, at 10:47 PM, Rhino wrote:
>
>>
>> Your original question said: "Need to select all (distinct) org_id
>> they have item_id 34, 36, 58 and 63. All of them, not only some of
>> them. "
>>
>> That's the question I answered with my suggested query.
>>
>> It sounds like that is not what you meant after all but I'm not sure
>> what you DO want with your query. Why are 2607 and 1520 the only
>> right answers?
>
> Because they are. I look at the database and "manually" found the
> result I have to get. What's wrong with my statement?
>
>> Based on your own query, it looks like you only want an org_id for
>> item_ids 34, 36, 58, and 63 if there are exactly 4 occurrences of
>> that org_id amongst the desired item_ids
>
> actually, there is mistake in my query, it should say "having
> count(org_id) >= 4"
> and, yes, that's what I want. I can get the correct list using the
> query I posted but I was hoping there is BETTER way.
>
>> but that wasn't in your statement of the problem. So please clarify
>> EXACTLY what you want. Giving an incomplete or contradictory
>> description of you want only wastes both your time and mine.
>
> As I stated earlier, English is not my first language and I was trying
> to do my best. Sorry for confusing you.
>
>
>>
>> --
>> Rhino
>>
>> On 2011-03-15 20:35, LAMP wrote:
>>>
>>> On Mar 15, 2011, at 6:18 PM, Rhino wrote:
>>>
>>>>
>>>> All you should need is this:
>>>>
>>>> select distinct org_id
>>>> from orders
>>>> where item_id in (34, 36, 58, 63)
>>>>
>>>> I'm assuming that the DISTINCT operator is available in the version
>>>> of MySQL that you are using. I don't currently have any version of
>>>> MySQL installed so I can't try this myself to be sure it works in
>>>> your version of MySQL.
>>>>
>>>> --
>>>> Rhino
>>>
>>> your query will give me every org_id that has ANY of item_id., I
>>> need org_id that has ALL of item_id. right?
>>> result would be
>>> 2607
>>> 1520
>>> 8934
>>> 7295
>>> 1649
>>> 8871
>>>
>>>
>>>
>>>>
>>>> On 2011-03-15 18:51, LAMP wrote:
>>>>> Hi,
>>>>> I need a help to build a query.
>>>>>
>>>>> Let's say there is a table orders (simplified, of course)
>>>>>
>>>>> CREATE TABLE orders (
>>>>> `item_id` int,
>>>>> `org_id` int,
>>>>> ) ENGINE=MyISAM
>>>>>
>>>>>
>>>>> item_id org_id
>>>>> 34 2607
>>>>> 34 2607
>>>>> 34 1520
>>>>> 36 2607
>>>>> 36 1520
>>>>> 36 8934
>>>>> 38 28
>>>>> 38 15
>>>>> 38 5
>>>>> 38 13
>>>>> 58 2607
>>>>> 58 2607
>>>>> 58 7295
>>>>> 58 1649
>>>>> 58 7295
>>>>> 58 1520
>>>>> 63 2607
>>>>> 63 2607
>>>>> 63 8871
>>>>> 63 7295
>>>>> 63 1520
>>>>> 65 15
>>>>> 65 20
>>>>> 95 1520
>>>>> 95 1520
>>>>> 95 7295
>>>>> 98 1520
>>>>> 98 7295
>>>>>
>>>>>
>>>>> Need to select all (distinct) org_id they have item_id 34, 36, 58
>>>>> and 63. All of them, not only some of them.
>>>>>
>>>>> Result is org_id=2607 and org_id=1520
>>>>>
>>>>> I can have it by
>>>>>
>>>>> select org_id
>>>>> from orders
>>>>> where item_id in (34, 36, 58, 63)
>>>>> group by org_id
>>>>> having count(org_id)=4
>>>>>
>>>>> but, I'm sure there is better solution?
>>>>>
>>>>> Thanks for any help.
>>>>>
>>>>> LAMP
>>>>>
>>>
>>>
>
>
