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From:Gary Date:April 20 2010 10:16pm
Subject:Getting Array to display on SELECT
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I'm frankly not sure if this is a MySQL question or PHP, but I thought I 
would start here.

I have a form that I have a (ever growing) list of checkboxes,  Here is a 
sample of  the code for it.

 <input name="keyword[]" type="checkbox" value="fox" />

It seems to go in, when I say seems to, I get a result of Array in the 
table, the code is listed below.  I have tried various solutions I found in 
searching the issue, but have only been able to so far get Array.

  echo '<table border="1"><th>Id Number</th><th>Date 
Entered</th><th>Caption</th><th>Where 
Taken</th><th>Keywords</th><th>Description</th><th>Image</th>';
  while ($row = mysqli_fetch_array($data)) {

    echo '<tr><td>' . $row['image_id']. '</td>';
   echo '<td>' . $row['submitted']. '</td>';
    echo '<td>' . $row['caption']. '</td>';
    echo '<td>' . $row['where_taken'] . '</td>';
    echo '<td>' . $row['keyword']. '</td>';
       echo '<td>' . $row['description'] . '</td>';
      if (is_file($row['image_file'])) {
      echo '<td><img src="'.$row['image_file'].'" width="100px" 
height="100px"/></td>';
      }

As a bonus question, does anyone have any idea why the image would show up 
in IE9, and not FF?

Thanks for your help.

Gary 


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Thread
Getting Array to display on SELECTGary21 Apr
  • RE: Getting Array to display on SELECTGavin Towey21 Apr
  • RE: Getting Array to display on SELECTMartin Gainty21 Apr