This will work:
select distinct X from a as a
where Y in(25)
and
not exists (select X from a as b where a.X = b.X and b.Y in(24))
----- Original Message -----
From: "Tim Molter" <tim.molter@*stripped*>
To: <mysql@*stripped*>
Sent: Sunday, December 27, 2009 4:04 PM
Subject: Is there a better way than this?
> I'm new to MySQL and I'm looking for some guidance. I have a table A,
> with two columns X and Y with the following data:
>
> | X | Y |
> 1 24
> 1 25
> 2 25
> 2 26
> 3 27
>
> I want my SQL query to return "2" following this verbose logic: SELECT
> DISTINCT X FROM A WHERE Y equals 25 and Y also does NOT equal 24.
>
> I came up with the following SQL, which gives me my desired result,
> but is there a better way to do it? Can it be achieved using MINUS or
> UNION somehow?
>
> BTW, I'm using IN here because I intend to replace the single numbers
> (24 and 25) with arrays that have 0 to N members.
>
> SELECT DISTINCT X FROM `A`
>
> WHERE X IN (
> SELECT X FROM `A` WHERE Y IN (25)
> )
>
> AND X NOT IN (
> SELECT X FROM `A` WHERE Y IN (24)
> )
>
> Thanks!
>
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