Victor,
> I beg to differ:
> mysql> select SKU, Quantity, Name, Price, p.sizes,
> p.colorsShadesNumbersShort from tem126080739853 t join products p on
> t.ProdID-p.ID <http://t.prodid-p.id/>;
...on t.ProdID-p.ID... _subtracts_ the two IDs. To match them use '='
rather than '-'.
PB
-----
Victor Subervi wrote:
> On Mon, Dec 14, 2009 at 12:37 PM, Peter Brawley <peter.brawley@stripped
>
>> wrote:
>>
>
>
>> > ... on t.ProdID-p.ID;
>>
>> Your join clause subtracts the two IDs, so it's on IDs that differ, and
>> apparently there aren't any.
>>
>>
>
> I beg to differ:
>
> mysql> select SKU, Quantity, Name, Price, p.sizes,
> p.colorsShadesNumbersShort from tem126080739853 t join products p on
> t.ProdID-p.ID <http://t.prodid-p.id/>;
> Empty set (0.00 sec)
>
> mysql> select * from tem126080739853;
> +----+--------+----------+----
> ---------+--------------------------+
> | ID | ProdID | Quantity | sizes | colorsShadesNumbersShort |
> +----+--------+----------+-------------+--------------------------+
> | 1 | 2 | 2 | Extra-small | navy-blue:CC7722 |
> +----+--------+----------+-------------+--------------------------+
> 1 row in set (0.00 sec)
> mysql> select SKU, Quantity, Name, Price, p.sizes,
> p.colorsShadesNumbersShort from tem126080739853 t join products p on
> t.ProdID-p.ID <http://t.prodid-p.id/>;
> Empty set (0.03 sec)
>
> mysql> select SKU, Quantity, Name, Price, t.sizes,
> t.colorsShadesNumbersShort from tem126080739853 t join products p on
> t.ProdID-p.ID <http://t.prodid-p.id/>;
> Empty set (0.00 sec)
>
> mysql> select ID, SKU, Name, Price from products;
> +----+----------+-------+--------+
> | ID | SKU | Name | Price |
> +----+----------+-------+--------+
> | 2 | prodSKU1 | name1 | 555.22 |
> +----+----------+-------+--------+
> 1 row in set (0.00 sec)
>
> t.ProdID == 2
> p.ID == 2
> That's a match.
> So why does my select join fail?
> TIA,
> V
>
>
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