From: Michael Dykman
Date: November 25 2009 2:39am
Subject: Re: How to concatenate a constant to an int?
List-Archive: http://lists.mysql.com/mysql/219491
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untested, but you are looking for something like this (formatted for humans=
):

select
       concat(
          ifnull(
            if(l.client_id,'L',null),
            ifnull(
                if(p.prospect_id,'P',null),
                'C')),
       c.contact_id) as reference_number,
from contact c
left join prospect p on c.contact_id =3D p.prospect_id
left join client l on p.prospect_id =3D l.client_id

- md


ifnull( if(l.client_id,'L',null),
   ifnull(if(p.prospect_id,'P',null),'C'))


On Tue, Nov 24, 2009 at 8:43 PM, Neil Aggarwal <neil@stripped> wr=
ote:
>> =A0 =A0 =A0 =A0 concat('C',c.contact_id) as ref
>
> That worked. =A0Thanks the the tip.
>
> Now, lets say I have three tables:
>
> contact
> =A0 =A0 =A0 =A0contact_id int
>
> prospect
> =A0 =A0 =A0 =A0prospect_id int
>
> client
> =A0 =A0 =A0 =A0client_id int
>
>
> If a contact is a prospect, it will have a line in
> both the contact and prospect table, with the same
> id value.
>
> If a contact is a client, it will have a line in
> the contact, prospect, and client table, all with
> the same id value.
>
> For example:
>
> =A0 =A0 =A0 =A0contact_id 1
>
> =A0 =A0 =A0 =A0contact_id 2
> =A0 =A0 =A0 =A0prospect_id 2
>
> =A0 =A0 =A0 =A0contact_id 3
> =A0 =A0 =A0 =A0prospect_id 3
> =A0 =A0 =A0 =A0client_id 3
>
> I want the ref numbers to be:
> =A0 =A0 =A0 =A0C1
> =A0 =A0 =A0 =A0P2
> =A0 =A0 =A0 =A0L3
>
> Is there a way to use a query to do that?
>
> Something like:
>
> create or replace view
> view_AllData as
> select
> =A0 =A0 =A0 =A0concat('C' or 'P' or 'L',c.contact_id) as reference_number=
,
> from contact c
> left join prospect p on c.contact_id =3D p.prospect_id
> left join client l on p.prospect_id =3D l.client_id
>
> Any ideas how to do this?
>
> Thanks
> =A0 =A0 =A0 =A0Neil
>
> --
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>
>



--=20
 - michael dykman
 - mdykman@stripped

"May you live every day of your life."
    Jonathan Swift

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