I agree with Claudio. You have your design correct. The only other thing you
need is the uid qualifier. Presumably you are using PHP or some other front
end to present your data. Your front end would request the user's name and
password, saving the uid in a variable and then issuing the select with a
WHERE clause that passes the uid in:
select * from articles A left joing article_types AT on A.article_type =
AT.Arcticle_types_id WHERE A.uid = <insert your variable here>
On Fri, Sep 11, 2009 at 8:22 AM, Claudio Nanni <claudio.nanni@stripped>wrote:
> A.J., It sounds good to me!
> You can be a little confused but you did it well,
> It seems you have all you need there.
> A) Yes
> B) select * from articles A left join article_types AT on A.article_type =
> 2009/9/11 AndrewJames <andrewhudds@stripped>
> > This is a bit of a long shot, but i really need some help and or directed
> > to the best reading resources.
> > as i begun building my database (as i went along), i now realise i have
> > stop coding and sit back and design the database properly before i can go
> > on.
> > However i am still unable to wrap my head around what data to put into
> > tables, and which columns i need to link to make the relationships. so
> > here is what i have.
> > TABLES:
> > users
> > -uid(pk)
> > -username
> > -password
> > articles
> > -article_id(pk)
> > -uid(fk)
> > -article_type(fk)
> > -article_subject
> > -article_body
> > article_types
> > -article_types_id(pk)
> > -article_type
> > So i want the user to be able to login and add articles.
> > I then want to be able to view all the articles the user has submitted.
> > So in my understanding i need to link the users.uid(pk) to the
> > articles.uid(fk) (so i know which user the article belongs to, please
> > correct and update me if i am wrong)
> > I am stuck at this point.
> > A) Have i created the right tables and columns for each table, AND
> > B) How do i link the articles.article_type to articles_type.type? (IF in
> > fact that is even the correct linkage)??
> > --
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