Ok, but in this way I can only detect if it's done ONE type of operation, for example if I
add a row and I remove an another one with this query I detect "no difference".
The principal point of the query that I want is to say "which" rows are changed (added or
deleted). I think it's not a easy query (or set of queries), but I want to create one for
However thanks for the hint about the difference between COUNT(1) and COUNT(*)!
From: Rolando Edwards <redwards@stripped>
Sent: Wednesday, August 05, 2009 23:12:09
Subject: RE: How to Detect MySql table update/difference
I have good news and bad news for you when it comes to MySQL 5.x.
Good News if you are counting against MyISAM
Bad News if you are counting against InnoDB
Just use either
SELECT table_rows FROM information_schema.tables WHERE table_schema='<given db
name>' and table_name='<given table name>';
SELECT COUNT(1) FROM <db-name>.<tbl-name>; (This will work in MySQL 4.x as
SELECT COUNT(1) FROM <db-name>.<tbl-name>, even though it can run faster than
will still count every row in the table anyway.
If you are using InnoDB, you are on your own !!!!
If you are using MyISAM, have fun !!!!
Rolando A. Edwards
MySQL DBA (CMDBA)
155 Avenue of the Americas, Fifth Floor
New York, NY 10013
AIM & Skype : RolandoLogicWorx
From: BS TLC [mailto:bstlc@stripped]
Sent: Wednesday, August 05, 2009 10:30 AM
Subject: How to Detect MySql table update/difference
Hi, I'm a novel developer of MySql and now I am trying to create a mysql query to detect
I query a database table every X seconds, and i want to get only the different rows in
the table. The result that I want to have is simply
TABLE (t = now) - TABLE (t = X second ago)
Every time that i query the database I store the table situation in another table, called
TABLE_TEMP, so the operation of difference detection is
TABLE_DIFERENCE = TABLE - TABLE_TEMP.
How can I do this query? The problem that I have is that I don't know the structure of
the table and I want to create a program with can be used for all types of data and
Please help me.
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