>I also want to find out the user's position relative to others
depending on the result.
For a given pUserID, something like this?
SELECT o1.userid,o1.result,COUNT(o2.result) AS rank
FROM object o1
JOIN object o2 ON o1.result < o2.result OR (o1.result=o2.result AND
GROUP BY o1.userid,o1.result
WHERE userid = pUserID;
Anders Norrbring wrote:
> I'm looking at a situation I haven't run into before, and I'm a bit
> puzzled by it.
> I have this table structure:
> Table USERS: userid, class
> Table OBJECT: userid, class, result
> Now I want to query the database for a certain user's result in a
> specified class, which is very, very easy. No problems.
> But, I also want to find out the user's position relative to others
> depending on the result.
> So, if the specified user's result is the 9:th best of all of the
> users, I want to have a reply from the DB query that say he has
> position number 9.
> I really can't figure out how to do that... Somehow I have to make
> MySQL calculate the position based on the value in the result column.