James Northcott / Chief Systems wrote:
>SELECT AID
>FROM AhasB WHERE BID in (1,2)
>GROUP BY AID
>HAVING count(BID) =2
Not quite, since that will catch aid's with two bid=1 rows or bid=2 rows:
SELECT * FROM t;
+------+------+
| i | j |
+------+------+
| 1 | 4 |
| 1 | 5 |
| 3 | 5 |
| 3 | 5 |
+------+------+
SELECT i
FROM t WHERE j in (4,5)
GROUP BY i
HAVING count(j) =2;
+------+
| i |
+------+
| 1 |
| 3 |
+------+
SELECT i,GROUP_CONCAT(j) AS list
FROM t
GROUP BY i
HAVING list='4,5';
+------+------+
| i | list |
+------+------+
| 1 | 4,5 |
+------+------+
PB
-----
> Peter Brawley wrote:
>> >I want to find all A's such that
>> >they have exactly B's 1 and 2
>> >SELECT A.ID, group_concat(BID ORDER BY BID) as Bs
>> >FROM A INNER JOIN AhasB ON A.ID=AID
>> >GROUP BY A.ID
>> >HAVING Bs='1,2'
>>
>> Why the join? Doesn't your ahasb bridge table already incorporate the
>> join logic? If your requirement is to retrieve all aid's with exactly
>> one instance of bid=1, exactly one with bid=2, and no other bid's,
>> why not just ...
>>
>> SELECT aid,GROUP_CONCAT(bid) AS list
>> FROM ahasb
>> GROUP BY aid
>> HAVING list='1,2';
>>
>> PB
>>
> I actually need some of the other columns from A, but you're correct,
> this does work. I did discover though that the ORDER BY in the
> group_concat is important, since MySQL doesn't always pick the same
> order for the list.
>
> ddevaudreuil@stripped wrote:
>> I think this will work:
>>
>> SELECT AID
>> FROM AhasB WHERE BID in (1,2)
>> GROUP BY AID
>> HAVING count(BID) =2
>>
>>
>> Donna
>>
>
> Thank you, this is actually very helpful. The where clause uses the
> index I have in the table to screen out many more rows early in the
> query, and it also very nicely avoids the string compare on the
> group_concat. I also wasn't aware that you could use an aggregate
> function in the HAVING clause without it appearing in the SELECT clause.
>
> Thanks again, this solves the problem quite elegantly, and I probably
> never would have thought of it.
>
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