Mike,
>What I need to do is find the last price_sold for each product_code.
SELECT
t1.product_code,t1.date_sold,t1.price_sold
FROM trans AS t1
LEFT JOIN trans AS t2
ON t1.product_code = t2.product_code
AND t1.price_sold < t2.price_sold
WHERE t2.product_code IS NULL
ORDER BY t1.product_code;
There's a bit of discussion at http://www.artfulsoftware.com/queries.php#7/
PB
-----
mos wrote:
> This should be easy but I can't find a way of doing it in 1 step.
>
> I have a Trans table like:
>
> Product_Code: X(10)
> Date_Sold: Date
> Price_Sold: Float
>
> Now there will be 1 row for each Product_Code, Date combination. So
> over the past year a product_code could have over 300 rows, one row
> for each day it was sold. There are thousands of products.
>
> What I need to do is find the last price_sold for each product_code.
> Not all products are sold each day so a product might not have been
> sold for weeks.
>
> The only solution I've found is to do:
>
> drop table if exists CurrentPrices;
> create table CurrentPrices select Prod_Code, cast(max(Date_Sold) as
> Date), -1.0 Price_Sold from Trans group by Prod_Code;
> alter table CurrentPrices add index ix_ProdCode (Prod_Code);
> update CurrentPrices CP, Trans T set CP.Price_Sold=T.Price_Sold and
> T.Date_Sold=CP.Date_Sold;
>
> Is there a way to shorten this? It may take 2-3 minutes to execute. I
> don't really need a new table as long as I get the Prod_Code and the
> last Date_Sold.
>
> TIA
> Mike
>
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