I have found in life that I get stuck, email a list and then figure it out
myself often. It was rather dumb!
Anyhow, here is what I have.
SELECT b.zip, b.state,b.storename, b.address1, b.address2, b.city, b.state,
b.zip, b.id,
ROUND((3956 * (2 * ASIN(SQRT(
POWER(SIN(((a.lat-b.lat)*0.017453293)/2),2) +
COS(a.lat*0.017453293) *
COS(b.lat*0.017453293) *
POWER(SIN(((a.lon-b.lon)*0.017453293)/2),2))))),2) AS distance
FROM zipcodes a, locations b
WHERE
a.zip = "63385"
GROUP BY b.id
HAVING distance <= 5
ORDER BY distance, storename;
Thanks
Steffan
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T E L 6 0 2 . 5 7 9 . 4 2 3 0 | F A X 6 0 2 . 9 7 1 . 1 6 9 4
Steffan A. Cline
Steffan@stripped Phoenix, Az
http://www.ExecuChoice.net USA
AIM : SteffanC ICQ : 57234309
Lasso Partner Alliance Member
---------------------------------------------------------------
> From: Jay Pipes <jay@stripped>
> Organization: MySQL, Inc.
> Reply-To: <jay@stripped>
> Date: Mon, 25 Sep 2006 09:59:19 -0400
> To: "Steffan A. Cline" <steffan@stripped>
> Cc: MySQL List <mysql@stripped>
> Subject: Re: Query missing rows in location of zip by distance
>
> On Mon, 2006-09-25 at 06:09 -0700, Steffan A. Cline wrote:
>> Basically all 6 should come up in the big query because they are within the
>> same zip and that any other locations within the same area. They all have
>> the same latitude and longitude but only 1 shows up.
>
> If they all have the same lat/long, then the distance from the centroid
> of your supplied zip code will be the same for all 6. Because you are
> grouping on the distance, only 1 record will return. Remove the GROUP
> BY distance.
>
> Cheers,
>
> Jay
>
