Lee
/>I think the formula is just right - very clever. But is it possible to
make
>sure that col1, col2 and col3 are all from the same record?
/
Different question, different answer I ween :-)
SET @n = <?>;
SELECT
id,
MIN( LEAST( ABS(@n-col1), LEAST( ABS(@n-col2), ABS(@n-cl3) ))) AS min
FROM tbl
GROUP BY id;
PB
-----
Lee Goddard wrote:
> Peter Brawley wrote:
>> />Is there an efficient way to find the closest numerical value, across
>> >three columns? I do not know if there is a way to find it across one. /
>>
>> Not sure about efficiency, but if the criterion number is @n, do you
>> mean ...
>>
>> SELECT LEAST( ABS(MIN(@n-col1)),
>> LEAST( ABS(MIN(@n-col2)),
>> ABS(MIN(@n-col3))
>> )
>> )
>> FROM ...
> I think the formula is just right - very clever. But is it possible to
> make sure that col1, col2 and col3 are all from the same record?
>
> Thanks in anticipation
> Lee
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