I may have a misunderstanding of this, but as I have been told, if I have a
table with 3 columns, Idx (an Index column, unique, auto-increment), Name,
Value (both varchar), and I try a command like this:
INSERT IGNORE INTO myTable SET Name = "Variable1", Value = "100";
INSERT IGNORE INTO myTable (Name, Value) VALUES("Variable1", "100");
AND I already have a row with the matching Name and Value columns matching in
value, that MySQL will detect that and not insert the redundant values. I've
also tried this without a unique, auto-increment column, just trying to
insert by specifying values for all 3 columns that already match an existing
row, and it still doesn't work.
I thought the IGNORE keyword was intended to be used to prevent duplicating
values, and that it matched the values in the INSERT statement (even if not
all columns in the table were given a value) against the ones in the table
and would NOT INSERT the row if it matched.
I'm using MySQL 4.023 on Debian Linux (installed through apt-get, not through
So this brings up a few questions: 1) Am I doing something wrong? 2) Is this
what INSERT IGNORE is supposed to do -- if not, what does it do?, and 3) If
this isn't what INSERT IGNORE does, how can I do what I *thought* it did --
insert only if the value doesn't already exist?