From: Peter Brawley Date: July 23 2005 6:14am Subject: Re: Totals Across Multiple Records List-Archive: http://lists.mysql.com/mysql/186849 Message-Id: <42E1E05A.6070104@earthlink.net> MIME-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit Albert, Your spec isn't entirely clear to me (eg if sd1 & sd2 were 'unique within each record', wouldn't there be zero rows where sd1=sd2?), but is this what you're looking for ... SELECT zz, COUNT(zz) as zzCount, SUM(IF(zz=sd1 AND sd1=sd2, 1, 0)) AS sd1sd2Count FROM ss GROUP BY zz; Peter Brawley http://www.artfulsoftware.com ----- Albert Padley wrote: > I would be grateful if those of you around this weekend could help me > figure out if what I'm after is possible. I've already spent hours > with the manual, the archives and my books. I've looked at JOINS and > TEMP TABLES but still can't come up with a solution. > > THE ENVIRONMENT: MySQL Version 4.0.24 (so subselects are not > available) > > THE TABLE > > CREATE TABLE `ss` ( > `tt` INT NOT NULL AUTO_INCREMENT , > `zz` INT( 3 ) NOT NULL , > `sd1` INT( 3 ) NOT NULL , > `sd2` INT( 3 ) NOT NULL , > PRIMARY KEY ( `id` ) > ); > > THE ISSUE: > > 1. xx, sd1 and sd2 all contain id numbers. These numbers are unique > within each record. > 2. I need to scan the table and create a table row for each id number > in zz that contains: > a. how many times each id appears in zz (This is easy using COUNT) > b. how many times each id appears in sd1 plus sd2. (If a total is > not possible, then a separate listing for sd1 and sd2 would suffice > (just like we have for zz) > c. The final table should list each id number with the following > columns: > > id number > total times id number appears in zz column > total times id number appears in sd1 & sd2 combined > > I sure hope this makes sense. > > Oh, one more thing. I can't change the table structure because I have > simplified it here for finding a solution. The above columns are part > of a much larger table that is currently in use for other purposes. > > Thanks. > > Albert Padley > > -- No virus found in this outgoing message. Checked by AVG Anti-Virus. Version: 7.0.323 / Virus Database: 267.9.2/55 - Release Date: 7/21/2005