[Sorry for cross-posting.]
This is in continuation with the above mentioned subject - I am trying to find the
'display data order' for the returned resultset. The following thread very well answers
my question:
http://lists.mysql.com/mysql/185626
a) SET @row=0;
b) SELECT (@row:=@row+1) AS row, ename, empno FROM emp ORDER BY empno;
+-----+--------+-------+
| row | ename | empno |
+-----+--------+-------+
| 1 | SMITH | 7369 |
| 2 | ALLEN | 7499 |
| 3 | WARD | 7521 |
| 4 | JONES | 7566 |
| 5 | MARTIN | 7654 |
+-----+--------+-------+
However, I am trying to use it in a perl script instead of from command line, and I am not
sure how exactly to do it. I need to execute both statements a & b together or else I
get
+-----+--------+-------+
| row | ename | empno |
+-----+--------+-------+
|NULL | SMITH | 7369 |
|NULL | ALLEN | 7499 |
|NULL | WARD | 7521 |
|NULL | JONES | 7566 |
|NULL | MARTIN | 7654 |
+-----+--------+-------+
How can I execute both (a) and (b) in my perl script?
Thanks for any help.
Nishi
