List: | General Discussion | « Previous MessageNext Message » | |

From: | Michael Stassen | Date: | December 12 2003 5:57am |

Subject: | Re: mean/median/mode | ||

View as plain text |

Mike Johnson wrote: > From: Robert Citek [mailto:rwcitek@stripped] > > >>Hello all, >> >>How can I calculate the mean/median/mode from a set of data using SQL? >> >>Mean seems to exist as the average (avg): >> select name, avg(value) from table group by name >> >>Is there a way to calculate median and mode with a group by clause? >> >>Median: the value at which 50% of the samples are above and >>below that value. >>Mode: the most common value > > > > For mode, this should work: > SELECT COUNT(value) AS mode FROM table GROUP BY value ORDER BY mode DESC LIMIT 1; I expect you meant to include the value itself: SELECT value, COUNT(value) AS mode FROM table GROUP BY value ORDER BY mode DESC LIMIT 1; This will work in many cases, but modes are tricky because: - There may not be a mode. For a value to be a mode, it must occur at least twice. - There may be more than one mode. Any value whose frequency matches the max frequency is a mode. For example, if values 2, 8, and 13 each occur 8 times, and all other values occur less frequently, then 2, 8, and 13 are modes. I feel that there must be a better way, but the following works: CREATE TEMPORARY TABLE counts SELECT val, COUNT(val) AS freq FROM data GROUP BY val HAVING COUNT(*)>1 ORDER BY freq DESC; SELECT @mode:=MAX(freq) FROM counts; SELECT val AS mode, freq FROM counts WHERE freq = @mode; DROP TABLE IF EXISTS counts; As a further wrinkle, considering the error inherent in statistical sampling, many statisticians would consider a value whose frequency is much greater than most frequencies but not quite as high as the max frequency to be a mode, or at least sort of a mode. For example, if values 36 and 48 have counts of 102, value 76 has a count of 98, and every other value occurs no more than 25 times, most would call the distribution trimodal (3 modes), even though 76 is not strictly a mode. Put another way, finding the modes is usually about finding the shape of the distribution. An alternative to calculating the modes would be to look for them visually by plotting the distribution. Something like this: SELECT val, COUNT(val) AS frequency, repeat('.',COUNT(val)) AS histogram FROM data GROUP BY val ORDER BY val; +------+-----------+-----------+ | val | frequency | histogram | +------+-----------+-----------+ | 1 | 3 | ... | | 2 | 8 | ........ | | 3 | 3 | ... | | 4 | 3 | ... | | 5 | 2 | .. | | 6 | 1 | . | | 7 | 3 | ... | | 8 | 8 | ........ | | 9 | 1 | . | | 11 | 2 | .. | | 12 | 3 | ... | | 13 | 8 | ........ | | 14 | 1 | . | | 15 | 1 | . | | 16 | 2 | .. | +------+-----------+-----------+ 15 rows in set (0.00 sec) You might want to know something about the size of your counts relative to your screen width before you try that. You could adjust accordingly, however, with something like SELECT val, COUNT(val) AS frequency, repeat('+',ROUND(COUNT(val)/10)) AS histogram FROM data GROUP BY val ORDER BY val; Michael

Thread | ||
---|---|---|

• mean/median/mode | Robert Citek | 4 Dec |

• Solved - median (was Re: mean/median/mode) | Robert Citek | 5 Dec |

• Re: Solved - median (was Re: mean/median/mode) | Michael Stassen | 11 Dec |

• RE: mean/median/mode | Mike Johnson | 4 Dec |

• Re: mean/median/mode | Michael Stassen | 12 Dec |

• RE: Solved - median (was Re: mean/median/mode) | emierzwa | 12 Dec |