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From:Jani Tolonen Date:October 3 1999 12:11pm
Subject:Trouble using RAND function
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Darla Baker writes:
 > I am trying to write a perl script that I will link to a
 > graphic on my web page so that when the graphic is clicked
 > it will take the user to a random favorite from my
 > collection of favorite urls.  I've been testing the SELECT
 > statement from the mysql command line using the following
 > statement:
 > 
 > SELECT _rowid,url from favorites WHERE _rowid = ROUND(
 > (RAND()*24) + 1 );
 > 
 > Right now there are 25 entries in the table and _rowid is an
 > auto_increment field.  When I execute the query I get an
 > empty set frequently and then occasionally it will return a
 > row.  What am I missing?  I am running mysql 3.22.22
 > 
 > Darla Baker
 > darla@stripped
 > 

Hi Darla,

The above should work. Can you please include in the mail the
output from the following: 

shell> mysqldump db_name favorites

Please show us also some output from the client when you execute
queries:

mysql> SELECT ROUND((RAND() * 24) + 1);

and

mysql> SELECT RAND();

couple of times.

Here is an alternative query you can try, for the meanwhile we
try to find out why the above doesn't work:

SELECT _rowid,url FROM favorites WHERE _rowid = (((RAND() * 24) % 24) + 1);

Regards,

- Jani

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Thread
Trouble using RAND functionDarla Baker3 Oct
  • Trouble using RAND functionJani Tolonen3 Oct
  • Re: Trouble using RAND functionDarla Baker3 Oct
    • Re: Trouble using RAND functionJani Tolonen3 Oct
      • Re: Trouble using RAND functionMartin Ramsch3 Oct
        • Re: Trouble using RAND functionMatthias Urlichs4 Oct
          • Re: Trouble using RAND functionMichael Widenius6 Oct
  • Re: Trouble using RAND functionStan P. van de Burgt3 Oct
    • Re: Trouble using RAND functionDarla Baker3 Oct
  • Re: Trouble using RAND functionDarla Baker3 Oct
    • Re: Trouble using RAND functionJani Tolonen4 Oct
  • Re: Trouble using RAND functionDarla Baker4 Oct