>>>>> "Narvaez," == Narvaez, Teresa <Teresa.Narvaez@stripped>
> writes:
Narvaez,> Hello,
Narvaez,> Thanks for your reply. This is the program I wrote to test
Narvaez,> that va_arg compiles. I kept it simple because I just wanted to
Narvaez,> prove that gcc will be able to compile it.
Narvaez,> I looked into my gcc-lib and did find 'stdarg.h'. What could
Narvaez,> be the problem? This error keeps coming up.
Narvaez,> Thank you, Teresa
Narvaez,> gcc -o testhash testhash.o libmysys.a ../dbug/libdbug.a
Narvaez,> ../strings/libmystrings.a -l
Narvaez,> m -lpthread -lmach -lexc -lc
Narvaez,> collect2: ld returned 1 exit status
Narvaez,> /bin/ld:
Narvaez,> Unresolved:
Narvaez,> __builtin_va_start
Narvaez,> *** Exit 1
Narvaez,> Stop.
Narvaez,> ===== beginning of program
Narvaez,> #include<stdio.h>
Narvaez,> #include<varargs.h>
Narvaez,> main()
Narvaez,> {
Narvaez,> char *par;
Narvaez,> int index=0;
Narvaez,> va_list ap;
Narvaez,> va_start(ap);
Narvaez,> par = va_arg(ap, char *);
Narvaez,> fprintf(stderr,"\npar = %s\n\n",par);
Narvaez,> va_end(ap);
Narvaez,> } /* main */
Hi!
Note that the above does only test varargs (the old interface) and not
the newer interface, stdarg, that MySQL uses!
Could you try again, but with the following program:
#include<stdio.h>
#include<stdarg.h>
int foo(int nr,...)
{
char *par;
int index=0;
va_list ap;
va_start(ap,nr);
par = va_arg(ap, char *);
fprintf(stderr,"\npar = %s\n\n",par);
va_end(ap);
}
main()
{
foo(1,"1");
exit(0);
}
Regards,
Monty
