At 10:18 -0700 1/19/03, Jeff Donnici wrote:
> > That would work, but it's not necessary. He should use a
>> LEFT JOIN, which will produce a row in the output for the
>> left table, whether or not any right table rows match it.
>> The syntax is in the MySQL manual.
>
>I appreciate the pointer to LEFT JOIN and have read through the site's
>documentation on it. Unfortunately, I don't see how that will help me
>get the non-existent dates in there with a count of 0. As Nasser pointed
>out, there's nothing to do if no rows for those dates exist. In the case
>of using a LEFT JOIN, I don't get what I'd be joining my table to...
>Sorry for being dense, but any help you can provide is most appreciated.
>Thanks!
Ah, yeah. Okay, that's right. So then you *will* need to do it
programmatically ... OR ... create a reference table that lists
each of the dates in which you're interested. Then do a LEFT JOIN
against that.
>
>J
