Re: Supplied argument is not a valid MySQL result resource!!

[Pekka Saarinen]

At 8/16/2002, you wrote:
>Hi,
>in the piece of code given below
>-----------
>$qid = mysql_query("
>  SELECT *
>  FROM 1_nodedata
>  WHERE id = $edit_id
>  ");
>  $frm = mysql_fetch_array($qid);
>-----------
>i get the follownig error:
>
>Warning: Supplied argument is not a valid MySQL result resource in
>/z/mercury/www/niksun/admin/add_doc.php on line 107
>element type:
>
>What is it happening so!!


$qid = mysql_query("
SELECT *
FROM 1_nodedata
WHERE id = '$edit_id'
");
if (!$qid ) {
print mysql_error();
exit;
}
$frm = mysql_fetch_array($qid);

or

$qid = mysql_query("
SELECT *
FROM 1_nodedata
WHERE id = '$edit_id'
");
if (!$qid ) {
print mysql_error();
}
if ($qid ) {
$frm = mysql_fetch_array($qid);
}



-------------------------
Pekka Saarinen
http://photography-on-the.net
-------------------------