Hi,
try :
> $qid = mysql_query("
> SELECT *
> FROM 1_nodedata
> WHERE id = '$edit_id'
> ");
> $frm = mysql_fetch_array($qid);
(what does echo "edit_id : $edit_id"; display ?)
Regards,
Jocelyn
----- Original Message -----
From: "Anil Garg" <anilg@stripped>
To: <mysql@stripped>
Sent: Thursday, August 15, 2002 11:12 PM
Subject: Supplied argument is not a valid MySQL result resource!!
> Hi,
> in the piece of code given below
> -----------
> $qid = mysql_query("
> SELECT *
> FROM 1_nodedata
> WHERE id = $edit_id
> ");
> $frm = mysql_fetch_array($qid);
> -----------
> i get the follownig error:
>
> Warning: Supplied argument is not a valid MySQL result resource in
> /z/mercury/www/niksun/admin/add_doc.php on line 107
> element type:
>
> What is it happening so!!
> regards
> anil
>
>
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